Hello, Let mathcal(S) the surface of equation z = ln(x^2y^2) it's the graph of your function f Remark that mathcal(S) is a revolution surface, because f(x,y) = g(r) where r = sqrt(x^2y^2) is the polar radius Actually, g(r) = ln(r^2) = 2 ln(r) So, graph the curve of equation z = 2ln(x) in the xOz plane
X^2+y^2+z^2=r^2 graph-Figure 2 The right triangle lies in the xyplaneThe length of the hypotenuse is r r and θ θ is the measure of the angle formed by the positive xaxis and the hypotenuseThe zcoordinate describes the location of the point above or below the xyplaneAnswer to Solved Sketch the graph of z = x^2 y^2 in R^3 Name the Transcribed image text Sketch the graph of z = x^2 y^2 in R^3 Name the surface (a) Paraboloid (b) Ellipsoid (c) Circle (d) Hyperboloid Find the domain of the function f(x, y) = ln(x y^2)
X^2+y^2+z^2=r^2 graphのギャラリー
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